std::transform_inclusive_scan - cppreference.com (original) (raw)
- Computes the inclusive prefix sum using op.
For each integer i in [0, std::distance(first, last)), performs the following operations in order:
- Creates a sequence which is formed by the values transformed from the elements of
[first,iter]in order by unary_op, where iter is the next ith iterator of first. - Computes the generalized noncommutative sum of the sequence over binary_op.
- Assigns the result to *dest, where dest is the next ith iterator of d_first.
- Same as (1), but each sequence created is formed by init followed by the elements of
[first,iter]in order.
2,4) Same as (1,3), but executed according to policy.
These overloads participate in overload resolution only if all following conditions are satisfied:
The generalized noncommutative sum of a sequence of elements over a binary operation binary_op is defined as follows:
- If the sequence only has one element, the sum is the value of the element.
- Otherwise, performs the following operations in order:
- Selects any two adjacent elements elem1 and elem2 from the sequence.
- Calculates binary_op(elem1, elem2) and replaces the two elements in the sequence with the result.
- Repeats steps 1 and 2 until there is only one element in the sequence.
The result is non-deterministic if the binary_op is not associative (such as floating-point addition).
For overloads (1,2), if binary_op(unary_op(*first), unary_op(*first)) is not convertible to the value type of decltype(first), the program is ill-formed.
For overloads (3,4), if any of the following values is not convertible to T, the program is ill-formed:
- binary_op(init, init)
- binary_op(init, unary_op(*first))
- binary_op(unary_op(*first), unary_op(*first))
If any of the following conditions is satisfied, the behavior is undefined:
- For overloads (1,2), the value type of decltype(first) is not MoveConstructible.
- For overloads (3,4),
Tis not MoveConstructible. - unary_op or binary_op modifies any element of
[first,last). - unary_op or binary_op invalidates any iterator or subrange of
[first,last].
Contents
[edit] Parameters
| first, last | - | the pair of iterators defining the range of elements to sum |
|---|---|---|
| d_first | - | the beginning of the destination range; may be equal to first |
| policy | - | the execution policy to use |
| init | - | the initial value |
| unary_op | - | unary FunctionObject that will be applied to each element of the input range. The return type must be acceptable as input to binary_op. |
| binary_op | - | binary FunctionObject that will be applied in to the result of unary_op, the results of other binary_op, and init if provided |
| Type requirements | ||
| -InputIt must meet the requirements of LegacyInputIterator. | ||
| -OutputIt must meet the requirements of LegacyOutputIterator. | ||
| -ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator. |
[edit] Return value
Iterator to the element past the last element written.
[edit] Complexity
Given \(\scriptsize N\)N as std::distance(first, last):
1-4) \(\scriptsize O(N)\)O(N) applications of unary_op and binary_op respectively.
[edit] Exceptions
The overloads with a template parameter named ExecutionPolicy report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicyis one of the standard policies, std::terminate is called. For any otherExecutionPolicy, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit] Notes
unary_op is never applied to init.
The parameter init appears last, differing from std::transform_exclusive_scan, because it is optional for this function.
[edit] Example
#include #include #include #include #include int main() { std::vector data{3, 1, 4, 1, 5, 9, 2, 6}; auto times_10 = [](int x) { return x * 10; }; std::cout << "10 times exclusive sum: "; std::transform_exclusive_scan(data.begin(), data.end(), std::ostream_iterator(std::cout, " "), 0, std::plus{}, times_10); std::cout << "\n10 times inclusive sum: "; std::transform_inclusive_scan(data.begin(), data.end(), std::ostream_iterator(std::cout, " "), std::plus{}, times_10); std::cout << '\n'; }
Output:
10 times exclusive sum: 0 30 40 80 90 140 230 250 10 times inclusive sum: 30 40 80 90 140 230 250 310