std::transform_reduce - cppreference.com (original) (raw)
- Applies transform to each pair of elements from the ranges
[
first1,
last1)
and the range of std::distance(first1, last1) elements starting from first2 and reduces the results (possibly permuted and aggregated in unspecified manner) along with the initial value init over reduce.
The result is non-deterministic if the reduce is not associative or not commutative (such as floating-point addition).
If any of the following values is not convertible to T
, the program is ill-formed:
- reduce(init, init)
- reduce(init, transform(*first1, *first2))
- reduce(transform(*first1, *first2), init)
- reduce(transform(*first1, *first2), transform(*first1, *first2))
Given last2 as the std::distance(first1, last1)th next iterator of first2, if any of the following conditions is satisfied, the behavior is undefined:
T
is not MoveConstructible.- transform or reduce modifies any element of
[
first1,
last1)
or[
first2,
last2)
. - transform or reduce invalidates any iterator or subrange of
[
first1,
last1]
or[
first2,
last2]
.
- Applies transform to each element in the range
[
first,
last)
and reduces the results (possibly permuted and aggregated in unspecified manner) along with the initial value init over reduce.
The result is non-deterministic if the reduce is not associative or not commutative (such as floating-point addition).
If any of the following values is not convertible to T
, the program is ill-formed:
- reduce(init, init)
- reduce(init, transform(*first))
- reduce(transform(*first), init)
- reduce(transform(*first), transform(*first))
If any of the following conditions is satisfied, the behavior is undefined:
T
is not MoveConstructible.- transform or reduce modifies any element of
[
first,
last)
. - transform or reduce invalidates any iterator or subrange of
[
first,
last]
.
2,4,6) Same as (1,3,5), but executed according to policy.
These overloads participate in overload resolution only if all following conditions are satisfied:
Contents
[edit] Parameters
first1, last1 | - | the pair of iterators defining the range of elements to be taken as the left operand of transform |
---|---|---|
first2 | - | the start of range of elements to be taken as the right operand of transform |
first, last | - | the pair of iterators defining the range of elements to be taken as the operand of transform |
init | - | the initial value of the generalized sum |
policy | - | the execution policy to use |
reduce | - | binary FunctionObject that will be applied in unspecified order to the results of transform, the results of other reduce and init. |
transform | - | unary or binary FunctionObject that will be applied to each element of the input range(s). The return type must be acceptable as input to reduce. |
Type requirements | ||
-InputIt1, InputIt2, InputIt must meet the requirements of LegacyInputIterator. | ||
-ForwardIt1, ForwardIt2, ForwardIt must meet the requirements of LegacyForwardIterator. |
[edit] Return value
1,2) The generalized sum of init and values over std::plus<>(), where values are the values transformed by std::multiplies<>(), each value is transformed from a pair of elements from the two input ranges.
3,4) The generalized sum of init and values over reduce, where values are the values transformed by transform, each value is transformed from a pair of elements from the two input ranges.
5,6) The generalized sum of init and values over reduce, where values are the values transformed by transform, each value is transformed from an element from the input range.
The generalized sum of a group of elements over an binary operation binary_op is defined as follows:
- If the group only has one element, the sum is the value of the element.
- Otherwise, performs the following operations in order:
- Takes any two elements elem1 and elem2 from the group.
- Calculates binary_op(elem1, elem2) and puts the result back to the group.
- Repeats steps 1 and 2 until there is only one element in the group.
[edit] Complexity
Given \(\scriptsize N\)N as std::distance(first1, last1) (or std::distance(first, last) for overloads (5,6)):
1,2) \(\scriptsize O(N)\)O(N) applications of std::plus<>() and std::multiplies<>() respectively.
3-6) \(\scriptsize O(N)\)O(N) applications of reduce and transform respectively.
[edit] Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit] Notes
transform is never applied to init.
If first == last or first1 == last1, init is returned, unmodified.
[edit] Example
transform_reduce
can be used to parallelize std::inner_product. Some systems may need additional support to get advantages of parallel execution. E.g., on GNU/Linux, the Intel TBB be installed and -ltbb option be provided to gcc/clang compiler.
#if PARALLEL #include #define PAR std::execution::par, #else #define PAR #endif #include #include #include #include #include #include #include // to parallelize non-associate accumulative operation, you'd better choose // transform_reduce instead of reduce; e.g., a + b * b != b + a * a void print_sum_squared(long const num) { std::cout.imbue(std::locale{"en_US.UTF8"}); std::cout << "num = " << num << '\n'; // create an immutable vector filled with pattern: 1,2,3,4, 1,2,3,4 ... const std::vector v{[n = num * 4] { std::vector v; v.reserve(n); std::generate_n(std::back_inserter(v), n, i = 0 mutable { return 1 + i++ % 4; }); return v; }()}; auto squared_sum = [](auto sum, auto val) { return sum + val * val; }; auto sum1 = std::accumulate(v.cbegin(), v.cend(), 0L, squared_sum); std::cout << "accumulate(): " << sum1 << '\n'; auto sum2 = std::reduce(PAR v.cbegin(), v.cend(), 0L, squared_sum); std::cout << "reduce(): " << sum2 << '\n'; auto sum3 = std::transform_reduce(PAR v.cbegin(), v.cend(), 0L, std::plus{}, [](auto val) { return val * val; }); std::cout << "transform_reduce(): " << sum3 << "\n\n"; } int main() { print_sum_squared(1); print_sum_squared(1'000); print_sum_squared(1'000'000); }
Possible output:
num = 1 accumulate(): 30 reduce(): 30 transform_reduce(): 30 num = 1,000 accumulate(): 30,000 reduce(): -7,025,681,278,312,630,348 transform_reduce(): 30,000 num = 1,000,000 accumulate(): 30,000,000 reduce(): -5,314,886,882,370,003,032 transform_reduce(): 30,000,000 // Compile-options for parallel execution on POSIX: // g++ -O2 -std=c++17 -Wall -Wextra -pedantic -DPARALLEL ./example.cpp -ltbb -o tr; ./tr