Injected-class-name - cppreference.com (original) (raw)

The injected-class-name is the unqualified name of a class within the scope of said class.

In a class template, the injected-class-name can be used either as a template name that refers to the current template, or as a class name that refers to the current instantiation.

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[edit] Explanation

In a class scope, the class name of the current class or the template name of the current class template is treated as if it were a public member name; this is called injected-class-name. The point of declaration of the name is immediately following the opening brace of the class (template) definition.

int X;   struct X { void f() { X* p; // OK, X is an injected-class-name ::X* q; // Error: name lookup finds a variable name, which hides the struct name } };   template struct Y { void g() { Y* p; // OK, Y is an injected-class-name Y* q; // OK, Y is an injected-class-name, but Y is not } };

Like other members, injected-class-names are inherited. In the presence of private or protected inheritance, the injected-class-name of an indirect base class might end up being inaccessible in a derived class.

struct A {}; struct B : private A {}; struct C : public B { A* p; // Error: injected-class-name A is inaccessible ::A* q; // OK, does not use the injected-class-name };

[edit] In class template

The injected-class-name of a class template can be used as a template-name or a type-name.

In the following cases, the injected-class-name is treated as a template-name of the class template itself:

Otherwise, it is treated as a type-name, and is equivalent to the template-name followed by the template-parameters of the class template enclosed in **<>**.

template<template<class, class> class> struct A;   template<class T1, class T2> struct X { X<T1, T2>* p; // OK, X is treated as a template-name   using a = A; // OK, X is treated as a template-name   template<class U1, class U2> friend class X; // OK, X is treated as a template-name   X* q; // OK, X is treated as a type-name, equivalent to X<T1, T2> };

Within the scope of a class template specialization or partial specialization, when the injected-class-name is used as a type-name, it is equivalent to the template-name followed by the template-arguments of the class template specialization or partial specialization enclosed in **<>**.

template<> struct X<void, void> { X* p; // OK, X is treated as a type-name, equivalent to X<void, void>   template<class, class> friend class X; // OK, X is treated as a template-name (same as in primary template)   X<void, void>* q; // OK, X is treated as a template-name };   template struct X<char, T> { X* p, q; // OK, X is treated as a type-name, equivalent to X<char, T>   using r = X<int, int>; // OK, can be used to name another specialization };

The injected-class-name of a class template or class template specialization can be used either as a template-name or a type-name wherever it is in scope.

template<> class X<int, char> { class B { X a; // meaning X<int, char>   template<class, class> friend class X; // meaning ::X }; };   template struct Base { Base* p; // OK: Base means Base };   template struct Derived : public Base<T*> { typename Derived::Base* p; // OK: Derived::Base means Derived::Base, // which is Base<T*> };   template<class T, template class U = T::template Base> struct Third {};   Third<Derived> t; // OK: default argument uses injected-class-name as a template

A lookup that finds an injected-class-name can result in an ambiguity in certain cases (for example, if it is found in more than one base class). If all of the injected-class-names that are found refer to specializations of the same class template, and if the name is used as a template-name, the reference refers to the class template itself and not a specialization thereof, and is not ambiguous.

template struct Base {};   template struct Derived: Base, Base { typename Derived::Base b; // error: ambiguous typename Derived::Base d; // OK };

[edit] injected-class-name and constructors

Constructors do not have names, but the injected-class-name of the enclosing class is considered to name a constructor in constructor declarations and definitions.

In a qualified name C::D, if

the qualified name is always considered to name C's constructor. Such a name can only be used in the declaration of a constructor (e.g. in a friend constructor declaration, a constructor template specialization, constructor template instantiation, or constructor definition) or be used to inherit constructors(since C++11).

struct A { A(); A(int);   template A(T) {} }; using A_alias = A;   A::A() {} A_alias::A(int) {} template A::A(double);   struct B : A { using A_alias::A; };   A::A a; // Error: A::A is considered to name a constructor, not a type struct A::A a2; // OK, same as 'A a2;' B::A b; // OK, same as 'A b;'

[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
CWG 1004 C++98 an injected-class-name could notbe a template template argument allowed, it refers to the classtemplate itself in this case
CWG 2637 C++98 the entire template-id could be an injected-class-name only the template name can