sqrtm - Matrix square root - MATLAB (original) (raw)

Syntax

Description

X = sqrtm([A](#buw3%5F2t-A)) returns the principal square root of the matrix A, that is, X*X = A.

X is the unique square root for which every eigenvalue has nonnegative real part. If A has any eigenvalues with negative real parts, then a complex result is produced. If A is singular, then A might not have a square root. If exact singularity is detected, a warning is printed.

example

[X,residual] = sqrtm([A](#buw3%5F2t-A)) also returns the residual, residual = norm(A-X^2,1)/norm(A,1). This syntax does not print warnings if exact singularity is detected.

[X,alpha,condx] = sqrtm([A](#buw3%5F2t-A)) returns stability factor alpha and an estimate of the matrix square root condition number of X in 1-norm, condx. The residual norm(A-X^2,1)/norm(A,1) is bounded approximately by n*alpha*eps and the 1-norm relative error in X is bounded approximately by n*alpha*condx*eps, where n = max(size(A)).

Examples

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Create a matrix representation of the fourth difference operator, A. This matrix is symmetric and positive definite.

A = [5 -4 1 0 0; -4 6 -4 1 0; 1 -4 6 -4 1; 0 1 -4 6 -4; 0 0 1 -4 6]

A = 5×5

 5    -4     1     0     0
-4     6    -4     1     0
 1    -4     6    -4     1
 0     1    -4     6    -4
 0     0     1    -4     6

Calculate the unique positive definite square root of A using sqrtm. X is the matrix representation of the second difference operator.

X = 5×5

 2    -1     0     0     0
-1     2    -1     0     0
 0    -1     2    -1     0
 0     0    -1     2    -1
 0     0     0    -1     2

Consider a matrix that has four square roots, A.

A=[7101522]

Two of the square roots of A are given by Y1 and Y2:

Y1=[1.56671.74082.61124.1779]

Y2=[1234]

Confirm that Y1 and Y2 are square roots of matrix A.

A = [7 10; 15 22]; Y1 = [1.5667 1.7408; 2.6112 4.1779]; A - Y1*Y1

ans = 2×2 10-3 ×

-0.1258 -0.1997 -0.2995 -0.4254

Y2 = [1 2; 3 4]; A - Y2*Y2

The other two square roots of A are -Y1 and -Y2. All four of these roots can be obtained from the eigenvalues and eigenvectors of A. If [V,D] = eig(A), then the square roots have the general form Y = V*S/V, where D = S*S and S has four choices of sign to produce four different values of Y:

S=[±0.372300±5.3723]

Calculate the square root of A with sqrtm. The sqrtm function chooses the positive square roots and produces Y1, even though Y2 seems to be a more natural result.

Y = 2×2

1.5667    1.7408
2.6112    4.1779

Input Arguments

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Input matrix, specified as a square matrix.

Data Types: single | double
Complex Number Support: Yes

Tips

Algorithms

The algorithm sqrtm uses is described in [3].

References

[1] N.J. Higham, “Computing real square roots of a real matrix,” Linear Algebra and Appl., 88/89, pp. 405–430, 1987

[2] Bjorck, A. and S. Hammerling, “A Schur method for the square root of a matrix,” Linear Algebra and Appl., 52/53, pp. 127–140, 1983

[3] Deadman, E., Higham, N. J. and R. Ralha, “Blocked Schur algorithms for computing the matrix square root,” Lecture Notes in Comput. Sci., 7782, Springer-Verlag, pp. 171–182, 2013

Extended Capabilities

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Usage notes and limitations:

Version History

Introduced before R2006a