What is Equilibrium? Definition, Types (original) (raw)

Last Updated : 16 May, 2026

When a reversible reaction takes place in a closed system, a stage is reached where the rate of the forward reaction becomes equal to the rate of the backward reaction. At this stage, no further change in the concentration of reactants and products is observed, even though the reactions are still continuing. This state is known as equilibrium.

equillibrium

Equilibrium Constant

When a chemical reaction reaches dynamic equilibrium, the rate of the forward reaction equals the rate of the backward reaction, and the concentrations of reactants and products remain constant.

The equilibrium constant is a numerical value that expresses the ratio of product concentrations to reactant concentrations at equilibrium, each raised to the power of their respective stoichiometric coefficient.

General Reaction

aA + bB ⇌ cC + dD

The equilibrium constant expression is:

K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}

Where,

If the reaction involves gases, the equilibrium constant can also be expressed in terms of partial pressures (Kp) instead of concentrations:

K_p = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b}

Where,

P represents the partial pressure of the gases.

Types of Equilibrium

Equilibrium is classified into different types based on the nature of the system:

**1. Homogeneous Equilibrium

An equilibrium in which all reactants and products are in the same phase (all gases, all liquids, or all aqueous solutions). The phase is uniform throughout the system.

**Example:

N2 (g) + 3H2 (g) ⇌ 2NH3 (g)

All species are gases.

2. Heterogeneous Equilibrium

An equilibrium in which reactants and products exist in more than one phase (solid, liquid, gas, or solution). Different phases are involved, e.g., solid with gas or liquid with gas.

**Example :

CaCO3 (s) ⇌ CaO (s) + CO2 (g)

Solid and gas are present.

Factors affecting Equilibrium

These factors influence how the system responds, but only temperature can change the equilibrium constant.

Equilibrium in Physical Change

Physical equilibrium occurs when a reversible physical process reaches a state where the rate of the forward process equals the rate of the backward process, and macroscopic properties remain constant. In physical equilibrium, no new substance is formed; only state or form changes.

1. Solid–Liquid Equilibrium

Equilibrium between a solid and its liquid occurs in a reversible melting/freezing process. Rate of melting equals to Rate of freezing.

**Example:

Ice (s) ⇌H2O (l)

2. Liquid–Vapor Equilibrium

Equilibrium between a liquid and its vapor occurs in a reversible evaporation/condensation process. Rate of evaporation equals to Rate of condensation.

**Example:

H2O (l) ⇌ H2O (g)

3. Solid–Vapor Equilibrium

Equilibrium between a solid and its vapor occurs in a reversible sublimation/deposition process. Rate of sublimation equals to Rate of deposition.

**Example:

I2 (s) ⇌ I2 (g)

Equilibrium in Chemical Change

In a reversible chemical reaction, chemical equilibrium is said to be established when the rate of the forward reaction equals the rate of the backward reaction, and the concentrations of reactants and products remain constant with time.

**Examples:

Ammonia Formation (Haber Process):

N2 (g) + 3H2 (g) ⇌ 2NH3 (g)

**Solved Examples

**Question 1: Find the equilibrium constant for the given reaction N 2 (gas)+ 3H 2 (gas) ⇌ 2NH 3 (gas) at 500 K temperature, when concentrations are N 2 **=2×10 -2 **M, H 2 **= 4×10 -2 M and NH 3 = 1×10 -2 M.

**Answer:

Use Equilibrium constant reaction which is,

Kc = ([P1] c[P2] d) / ([R1] a[R2] b)

Therefore,

Kc = ([NH3] 2) / ([N2][H2] 3)

= (1×10-2) 2 / (2×10-2)(4×10-2) 3

= 78.1

**Question 2: Find the equilibrium constant for the given reaction PCl 5 ⇌ PCl 3 **+ Cl 2 at 500 K temperature, when concentrations are PCl 5 = 1.5 M, PCl 3 **= 2 M and Cl 2 = 2 M.

**Answer:

Kc = [PCl3][Cl2] / [PCl5]

= [2][2] / [1.5]

= 2.67

**Question 3: Find the equilibrium constant for the given reaction:

**N 2 + O 2 ⇌ 2NO at 800 K temperature,

**when concentrations are NO = 1×10 -2 M, O 2 = 2×10 -2 M and N 2 = 2×10 -2 M.

**Answer:

Kc can be calculated by using formula:

Kc = [NO] 2 / [N2][O2]

= [1×10-2] 2 / [2×10-2][2×10-2]

= 0.25