Quadrilateral Formulas (original) (raw)
Last Updated : 23 Jul, 2025
A quadrilateral is a closed figure and a type of polygon which has four sides or edges, four angles, and four corners or vertices. The word quadrilateral is derived from the Latin words "quad", a variant of four, and "latus", meaning side. It is also called a **tetragon, derived from the Greek word "tetra", meaning four, and "gon" meaning corner or angle.
In this article, we will learn about Quadrilateral Definition, various Quadrilateral Formulas, related examples and others in detail.
Table of Content
- Quadrilateral Definition
- Types of Quadrilateral
- Formulas of Quadrilateral
- Area of Quadrilaterals
- Perimeter of Quadrilaterals
Quadrilateral Definition
A quadrilateral is formed by joining four non-collinear points. The sum of the interior angles of a quadrilateral is always equal to 360 degrees.

It is not necessary that all four sides of a quadrilateral are equal in length. Thus, we can have different types of quadrilaterals based on their sides and angles.
Here, ABCD is a quadrilateral, with four sides namely AB, BC, CD, DA, four angles ∠A, ∠B, ∠C, ∠D, and the lines joining A to C and B to D are two diagonals of the quadrilateral.
Types of Quadrilateral
Based on their properties, quadrilaterals are divided into two major types:
- **Convex Quadrilaterals: Quadrilaterals that have one interior angle greater than 180° and one diagonal lies outside the quadrilateral are called concave quadrilaterals.
- **Concave Quadrilaterals: Quadrilaterals that have all four interior angles less than 180° are called concave quadrilaterals.
Types of Convex Quadrilaterals
Various types of convex quadrilateral are:
**Parallelogram
A parallelogram is a quadrilateral with two pairs of parallel sides. The opposite sides of a parallelogram are of equal length and the opposite angles of a parallelogram are also equal. The image for the same is added below:

**Rectangle
A **Rectangle is a type of quadrilateral that has its parallel sides equal to each other and all four angles 90°. Hence, it is also called an equiangular quadrilateral. The image for the same is added below:

**Square
A quadrilateral with four equal sides and four equal angles is called a Square. The image for the same is added below:

**Rhombus
A **Rhombus is a type of parallelogram with four equal sides and equal opposite angles. The image for the same is added below:

**Trapezium
A trapezium is a kind of quadrilateral having only one pair of sides parallel to each other. The image for the same is added below:

**Kite
A quadrilateral having pair of adjacent sides equal is known as Kite. The image for the same is added below:

**Formulas of Quadrilateral
There are two basic formulas for quadrilaterals
**Area of Quadrilaterals
In geometry, the area can be defined as the space occupied by a flat shape or the surface of an object. The area of a figure is the number of unit squares that cover the surface of a closed figure. The area is measured in square units such as square centimeters, square feet, square inches, etc.
| **Area of Parallelogram | **= Base × Height |
|---|---|
| **Area of Rectangle | **= Length × Width |
| **Area of Square | **= Side × Side |
| **Area of Rhombus | **= 1/2 × (diagonal)1 × (diagonal)2 |
| **Area of Trapezium | = 1/2 × Height × (Length1 + Length2) |
| **Area of Kite | **= 1/2 × (diagonal)1 × (diagonal)2 |
**Perimeter of Quadrilaterals
In geometry, the perimeter can be defined as the path or the boundary that surrounds a shape. It can also be defined as the length of the outline of a shape.
Since we know that quadrilateral has four sides, therefore, the perimeter of any quadrilateral say, ABCD, is given by
| **Perimeter of Parallelogram | **= 2×(Base + Side) |
|---|---|
| **Perimeter of Rectangle | **= 2×(Length + Width) |
| **Perimeter of Square | **= 4 × Side |
| **Perimeter of Rhombus | **= 4 × Side |
| **Perimeter of Trapezium | = Sum of all Sides |
| **Perimeter of Kite | **= 2×(a + b), where a, and b are Adjacent Pairs |
**Sample Problems on Quadrilateral Formulas
**Problem 1: If 20cm and 10cm are diagonal lengths of a kite, then find the area of the kite.
**Solution:
Given:
_Length of diagonal1 = 20cm
_Length of diagonal2 = 10cm
_Area of Kite =1/2 × diagonal1 × diagonal2
_Area =1/2 ×20 ×10 = 100cm 2
**Problem 2: How can we find the perimeter of an irregular Quadrilateral?
**Solution:
_To determine the perimeter of an irregular quadrilateral we can simply add the length of the outer sides of the quadrilateral. Because perimeter is nothing but the total length of the periphery of any shape.
**Problem 3: Find the area of the trapezium whose length of parallel sides is 7cm and 18cm respectively and the height of the trapezium is 10cm.
**Solution:
Given,
_Length of parallel sides of Trapezium,
_Length 1 = 7cm
_Length 2 = 18cm
_Height of Trapezium = 10cm
_we know that, Area of Trapezium = 1/2 × Height × (Length1 + Length2)
_Therefore,
_Area = 1/2 × 10 ×(7 +18)
=125cm 2
_Hence, Area of the given trapezium is 125cm 2
**Problem 4: The perimeter of a quadrilateral is 90cm and the length of the three sides are AD = 23cm, AB = 28cm and BC = 18cm. Find the length of the fourth side i.e, CD.

**Solution:
Given,
_Length of side AB = 28cm
_Length of side BC = 18cm
_Length of side AD = 23cm
_Let the length of side CD = x cm
_we know that,
_Perimeter = AB + BC + CD + AD
_This implies,
_90 = 28 + 18 + x +23
_90 = 69 + x
_x = 21
_Hence, the length of side AD = 21cm
**Problem 5: If the area of a rhombus is 70cm 2 and the base is 15cm, then find out the height of the given rhombus.
**Solution:
_Area = 70cm 2
_Base = 15cm
_Since Area of Rhombus = Height × Base
_This implies,
_70 = Height × 15
_Height = 70/15
_Height = 4.67cm
**Problem 6: Write down the formula to calculate the length of the diagonal of a rectangle.
**Solution:
_Diagonal of a rectangle is a line segment drawn to connect any two non-adjacent vertices of a rectangle. A rectangle can have a maximum of two diagonals of equal length.
_A diagonal rectangle divides the rectangle into two right-angle triangles. Therefore we can easily calculate the length of diagonals using the Pythagoras Theorem, where the diagonals are considered as the hypotenuse of the right triangle.
_Consider triangle BCD,
_Since the triangle BCD is a right angle triangle,
_Therefore, (BC) 2 = (BD) 2 + (CD) 2
(BC) 2 = (width) 2 + (length) 2
BC = √(width) 2 _+ (length) 2
**Problem 7: Find the perimeter of a parallelogram whose base is 12cm and height is 23cm.
**Solution:
_Base length of given parallelogram = 12cm
_Height of given parallelogram = 23cm
_Perimeter of a parallelogram = 2×(a + b)
_where a = 12cm and b = 23cm
_Perimeter of parallelogram = 2×(12 + 23)
= 70cm
_Hence, the perimeter of the given parallelogram is 70cm
