polar coordinates (original) (raw)

Then r≥0, θ∈[0,2⁢π) related to (x,y) by

x⁢(r,θ) = r⁢cos⁡θ,
y⁢(r,θ) = r⁢sin⁡θ,

are the polar coordinates for (x,y). It is simply written (r,θ).

The polar coordinates of Cartesian coordinates(x,y)∈ℝ2∖{0} are

r⁢(x,y) = x2+y2,
θ⁢(x,y) = arctan⁡(x,y),

where arctan is defined here (http://planetmath.org/OperatornamearcTanWithTwoArguments).

Polar basis.Polar coordinates are equipped with an orthonormal base {𝐞𝐫,𝐞θ}, which can be defined in terms of the standard cartesian base {𝐢,𝐣} in ℝ2 as follows.

[𝐞𝐫𝐞θ]=[cos⁡θ⁢𝐢+sin⁡θ⁢𝐣-sin⁡θ⁢𝐢+cos⁡θ⁢𝐣],

where 𝐞𝐫,𝐞θ are so-called radial and traverse or angular vector, respectively. Since these vectors are variable in direction, they are differentiableMathworldPlanetmathPlanetmath. In fact,

[d⁢𝐞𝐫d⁢θd⁢𝐞θd⁢θ]=[𝐞θ-𝐞𝐫].

The geometrical action of the derivativePlanetmathPlanetmath operator d/d⁢θ is like a rotation operator that rotates each base vector a counter-clockwise angle equals to π/2.

Position vector. For an arbitrary point of polar coordinates (r,θ), its position vector comes given by the single equation

RelationsMathworldPlanetmathPlanetmath with complex numbers.When the Euclidean planeMathworldPlanetmath ℝ2 is identified with ℂ by

it is possible to define multiplications on ℝ2. Via polar coordinates, the formulaMathworldPlanetmathPlanetmath for this multiplication becomes very simple, thanks to Euler’s formula (http://planetmath.org/EulerRelation)

Thus, we have the following identification:

(r,θ)↔(x,y)↔x+y⁢i=r⁢cos⁡θ+(r⁢sin⁡θ)⁢i=r⁢ei⁢θ.

If P=(r1,θ1)and Q=(r2,θ2), the productPlanetmathPlanetmath of P and Q works out to be(r1⁢r2,θ1+θ2). (Even if one is not familiar with the complex exponentialPlanetmathPlanetmath, this assertion may be checked directly using the angle sum identities for cos and sin.)

Multiplications of polar coordinates have some simple geometricinterpretationsMathworldPlanetmathPlanetmath. For example, if R=(1,α) and Q=(r,β), then Q→R⁢Q given by(1,α)⁢(r,β)=(r,α+β) is the rotationMathworldPlanetmath of Q by angle α. If S=(t,0), then (t,0)⁢(r,β)=(t⁢r,β) can be viewed as the scalingMathworldPlanetmath of Q along the ray O⁢Q→by t. Note also that multiplication by (t,0) has the same effect as multiplication by the scalar t.

For more on polar coordinates, including their construction and extensionsPlanetmathPlanetmath on domain of polar coordinates r and θ, see here (http://planetmath.org/ConstructionOfPolarCoordinates).

Calculus in polar coordiantes.For reference, here are some formulae for computing integrals and derivatives in polar coordinates. The JacobianMathworldPlanetmathPlanetmath for transforming from rectangular to polar cordinates is

so we may compute the integral of a scalar field f as

Partial derivativeMathworldPlanetmath operators transform as follows:

∂∂⁡x =cos⁡θ⁢∂∂⁡r-1r⁢sin⁡θ⁢∂∂⁡θ
∂∂⁡y =sin⁡θ⁢∂∂⁡r+1r⁢cos⁡θ⁢∂∂⁡θ
∂∂⁡r =cos⁡θ⁢∂∂⁡x+sin⁡θ⁢∂∂⁡y
∂∂⁡θ =-r⁢sin⁡θ⁢∂∂⁡x+r⁢cos⁡θ⁢∂∂⁡y