Scalar Matrix (original) (raw)

Last Updated : 21 Aug, 2025

A scalar matrix is a square matrix in which all principal diagonal elements are equal and the remaining elements are zero. It is a special case of a **diagonal matrix and can be obtained when an **identity matrix is multiplied by a constant value.

The matrix given below is a scalar matrix of order "4 × 4." We can observe that all its main diagonal elements are the same, while the rest of the elements are zeros.

A =\left[\begin{array}{cccc} 5 & 0 & 0 & 0\\ 0 & 5 & 0 & 0\\ 0 & 0 & 5 & 0\\ 0 & 0 & 0 & 5 \end{array}\right]

A scalar matrix can be obtained when an identity matrix is multiplied by a constant value. In the image given below, we can observe that when an identity matrix is multiplied by a constant "k," a scalar matrix is obtained.

scalar_matrix-formula

Scalar Matrix

**Scalar Matrix = k × Identity Matrix

**Condition for a Scalar Matrix

Consider a square matrix A that has "i" rows and "j" columns, and let "aij" be an element of the matrix at row number "i" and column number "j."
The following two requirements must be satisfied for matrix A to be a scalar matrix:

Examples of Scalar Matrix

A = \left[\begin{array}{cc} -6 & 0\\ 0 & -6 \end{array}\right]

P = \left[\begin{array}{ccc} k & 0 & 0\\ 0 & k & 0\\ 0 & 0 & k \end{array}\right]

Properties of a Scalar Matrix

Following are the properties of the scalar matrix

If A = \left[\begin{array}{cc} k & 0\\ 0 & k \end{array}\right], then A-1 = \left[\begin{array}{cc} \frac{1}{k} & 0\\ 0 & \frac{1}{k} \end{array}\right] (for k ≠ 0).

Scalar vs Diagonal vs Identity Matrix

All these matrix seems similar but there is a slight difference between each of them below is the table showing the difference between them:

Scalar Matrix Identity Matrix Diagonal Matrix
Diagonal elements equal to a constant k (k≠0). Diagonal elements equal to 1. Diagonal elements can have any value.
All off-diagonal elements are 0. All off-diagonal elements are 0. All off-diagonal elements are 0.
Special type of diagonal matrix and includes the identity matrix if k = 1. A special case of both scalar and diagonal matrices where k = 1. A diagonal matrix is the most general form.
\left[\begin{array}{ccc} k & 0 & 0\\ 0 & k & 0\\ 0 & 0 & k \end{array}\right] \left[\begin{array}{ccc} 1 & 0 & 0\\ 0 & 1 & 0\\ 0 & 0 & 1 \end{array}\right] \left[\begin{array}{ccc} 1 & 0 & 0\\ 0 & 9 & 0\\ 0 & 0 & 2 \end{array}\right]
The uniform diagonal value makes it "scalar". Multiplying any matrix by an identity matrix leaves the matrix unchanged. General diagonal elements without uniformity or restrictions.

Operation on Scaler Matrix

For any two matrices of the order m × n, let us say, A = [aij] and B = [bij] and take two scalers 'a' and 'b' Then the scalar multiplication is:

The multiplication of a scalar matrix (say A) with another matrix (say B) is equal to the multiplication of the constant element of the scalar matrix (A) with all the elements of the matrix (B).

**Also Check

Solved Examples on Scalar Matrix

**Example 1: Calculate the determinant of a scalar matrix given below.

A = \left[\begin{array}{ccc} -3 & 0 & 0\\ 0 & -3 & 0\\ 0 & 0 & -3 \end{array}\right]

**Solution:

Given matrix A = \left[\begin{array}{ccc} -3 & 0 & 0\\ 0 & -3 & 0\\ 0 & 0 & -3 \end{array}\right]

|A| = −3[(−3 × −3) − 0] − 0 + 0
|A| = −3(9) = −27

Hence, the determinant of the given scalar matrix is −27.

**Example 2: Give an example of a scalar matrix that has three rows and three columns.

**Solution:

The order of a scalar matrix that has three rows and three columns is "3 × 3." The matrix given below represents a scalar matrix of order "3 × 3," where all the principal diagonal elements are equal, and the rest of the elements are zeros.

B = \left[\begin{array}{ccc} 6 & 0 & 0\\ 0 & 6 & 0\\ 0 & 0 & 6 \end{array}\right]

**Example 3: Determine the inverse of the scalar matrix given below.

P = \left[\begin{array}{cc} \frac{1}{2} & 0\\ 0 & \frac{1}{2} \end{array}\right]

**Solution:

The given matrix P = \left[\begin{array}{cc} \frac{1}{2} & 0\\ 0 & \frac{1}{2} \end{array}\right]

Now, P-1 = Adj P/|P|

|P| = 1/2(1/2 − 0) − 0 = 1/4

P-1 = \left[\begin{array}{cc} \frac{1}{2} & 0\\ 0 & \frac{1}{2} \end{array}\right] / (1/1/4)

P-1 = 4 × \left[\begin{array}{cc} \frac{1}{2} & 0\\ 0 & \frac{1}{2} \end{array}\right]

P-1 = \left[\begin{array}{cc} 2 & 0\\ 0 & 2 \end{array}\right]

**Example 4: Find the value of (a + b + c) if the matrix given below is a scalar matrix.

C = \left[\begin{array}{ccc} a & 0 & 0\\ 0 & -2 & b+3\\ c-5 & 0 & -2 \end{array}\right]

**Solution:

If the given matrix is a scalar matrix, then all its principal diagonal elements are equal, and the rest of the elements are zeros.

So, a = −2
b + 1 = 0 q = −3
c − 2 = 0 c = 5

Now, a + b + c = −2 + (−3) + 5
= −5 + 5 = 0

Hence, the value of (a + b + c) is 0 if matrix A is a scalar matrix.